Help! Write the equation of a line through C that it parallel to AB Writhe the equation of a line through B that is perpendicular to AC PIC BELOW
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@shubhamsrg think you could help me out...sorry if I tag u in alota of questions
what is the slope of line AB ?
slope is x2-x1 y2-y1 right I cant remember the formula right now
slope is ( y2 -y1 )/(x2 -x1) plug in values, and tell me, what is the slope ?
AB=0.17
I meant 0.75
yes, 0.75 is right now, equation of a line passing through given point and known slope is (y-y1) = m(x-x1) plug in m=0.75 x1 = 5 y1 = -1
im a little lost now... -1-5=0.74-5
hmm, no it will be (y- (-1) ) = 0.75 (x - 5)
that's the equation??
or answer lol
yes.
ok thank you
what about the equation of a line through b that is perpendicular to AC do the same thing only use the slope for AC?
yes, use the slope of AC. this time it is perpendicular, so you'll have to multiply the slope by -1and take its reciprocal. might sound bit complicated but is easy
ok so slope of AC is 5 so it would be (y-(-1)=5(x-5)?
slope of AC is not 5, recheck
is it -7
close, but not exactly right. give it another try :)
7/-1
nopes, it should be -1/7
ooh ok I got it I did it upside down
but then I do the same thing like I put above only with a 7
nvm, so now this is perpendicular, so you revrse this and take its -ve reverse = -7 negative = 7
ok I get theat
now, this line passes through (2,3) so eqn will be (y-3) = 7(x-2)
oooh ok
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