Question

Help, pleeeaaaseee??
Find the zeros of g(x) = 3x2 - x + 8 by using the Quadratic Formula.

Answer 1

quadratic formula is

\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

for equations of such form g(x)=ax^2+bx+c

Answer 2

So, you plug in a b and c??

Answer 3

yep

Answer 4

so for you

a=3
b=-1
c=8

Answer 5

So I get......... \[x=\frac{ -(-1) \pm \sqrt{(-1)^2 - 4(3)(8)} }{ 2(3) }\]

\[x=\frac{ 1\pm \sqrt{1-96} }{ 6 }\]

Answer 6

is that right?

Answer 7

Nevermind, I got it. Thank you :)