Question

In a statewide cat show, 30% of the cats are eliminated each day. If the competition starts with 3,000 cats, to the nearest integer, how many cats will be present at the start of the 5th day?

Answer 1

I use the Geometric sequence formula but it doesn't add up

Answer 2

Try to make a new formula:

End of first day:
3000*0.7 cats

End of second day:
(3000*0.7) * 0.7 cats

End of third day:
[(3000*0.7)*0.7] * 0.7 cats

See where this is going?

3000 * (0.7)^[# of days]

So after 5 days, how many cats are left?

Answer 3

by your math, 504. The options are: A=259, B = 480, C = 720, D = 1229

Answer 4

Read the question. "How many cats will be present at the start of the 5th day?"

This is the END of the FOURTH day.

Answer 5

I put in 3000 * (0.7)^5

That's 5 days... Am I using the right formula? I thought I was...

Answer 6

"How many cats will be present at the START of the FIFTH day?"

Does your day not begin at midnight?

Answer 7

It does, should I use 6?

Answer 8

"How many cats will be present at the START of the FIRST day?"
"How many cats will be present at the START of the SECOND day?"
"How many cats will be present at the START of the THIRD day?"
"How many cats will be present at the START of the FOURTH day?"
"How many cats will be present at the START of the FIFTH day?"

Answer 9

Oke... How does the START of the day make things different... bro, could ya just give me the answer? It's my last geometric question, I did the rest

Answer 10

The answer is C. 720 (720.3 to be exact).

At the start of the fifth day, no cats have been eliminated yet. So it's the same as the END of the FOURTH day.

Answer 11

Oh! That went right over my head... Thx man.

Answer 12

Sorry if I seem rude. I want to make sure you understand instead of just copying my answers :)

Answer 13

Its cool, but how did you use 0.7 for r when it said 30%?