Question

Find the ratio of the width of a regulation size basketball court to its perimeter. 50 ft (width) 94 ft (length)

Answer 1

P = 2(L+W)

P = 2(94+50)

P = ???

Answer 2

i was wondering where did you get the 2?

Answer 3

well to find the perimeter of any rectangle, you add the 4 sides

BUT

the opposite sides are equal

Answer 4

so you could do it the long way

94+94+50+50

Answer 5

or you could write it as

2*94 + 2*50

Answer 6

then factor out the 2

2*(94 + 50)

Answer 7

yea the perimeter is 288 right cos i added all the sides but im stuck right there

Answer 8

now compute the ratio

width : perimeter

50 : 288

25 : 144 ... divide both parts by 2

Answer 9

yea like i dont know were the 2 comes from is it automatically there?

Answer 10

do you see how I went from 94+94+50+50 to 2*94 + 2*50

Answer 11

where i am stuck at is getting the 2 like i had no idea that you had to include the 2 that is why my solution was wrong

Answer 12

you got 50:288 as your answer right?

Answer 13

well what i did was divide 50 and 288 and i got 5 38/50 and my solution was wrong. i was wondering how 2 is involved like what you put 2 times 94 and 2 times 50

Answer 14

all they want is the ratio of width:perimeter

Answer 15

so you replace width with 50 and perimeter with 288 to get 50:288

Answer 16

then you divide both parts by 2 to get 25:144

Answer 17

and that's as far as you can go

Answer 18

okay so for every question like this would i have to divide by 2 ?

Answer 19

I only divided by 2 because 50 and 288 have the common factor of 2

Answer 20

The idea was to reduce the ratio as much as possible

Answer 21

25 and 144 have no factors in common (other than 1), so that's why 25:144 is fully reduced now

Answer 22

ohhhhhhhh! know i get it i did the total opposite thank you so much ! :)

Answer 23

you're welcome

glad it's clicking now

Answer 24

yea it did now thanks so much

Answer 25

sure thing