help needed with wrong questions http://prntscr.com/zfsdg
can you tell me is the answer correct
is that your working below the question???
Assume everything changes uniformly? \(\Delta\)Linear Distance is a factor of 2 \(\Delta\)Surface Area is a factor of 2^2 = 4 \(\Delta\)Volume is a factor of 2^3 = 8
yea i dont get qhat is the maistake there can you please show me the working
What working? 71*8 = ??
i did the solution please tell me what to do
is it really wrong
\(71 = \dfrac{4}{3}\pi r^{3}\) What is \(\dfrac{4}{3}\pi (2r)^{3}\)
where i have stated 2r^2
ka please you tell me what's wrong with the answer
i got 568 as the answer when i worked it out.....if it is correct i would explain how i arrived at it....
ok
is my answer correct??
Whoops. width doubled. New calculation.
oh this not good yesterday say i did it with factor of 2 but one of viewer said to do it by the factor of 4 i did it 4 the one i did with 2 http://prntscr.com/zchy0 see when i did it this way my teacher said its wrong
do you have the answer to the question??
no sorry
i do not if i am right but i this is how i worked it out.....
knowing that the volume of any object ids directly proportional to the cube of any of its length, in symbols,\[V \alpha l ^{3}\]
Yes. You are correct. If the length doubles, the surface area is multiplied by 4 and the volume is multiplied by 8.
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