Find the angle measure between 0 and 90 degrees that satisfies sin(theta)=1/2
pi/6 radians
or 30 degrees
^^
thanks, but how did you get it? the work is the most important part as we are allowed to use wolfram alpha and all that.
?
its just basic trigonometric angles .You need to learn some basic values for particular angles
yes... pi/6 or 30 degrees are common angles in trig and the sine, cosine and tangent of this (and other common angles) is important to remember... but as far as the proof that sin(30 degrees) = 1/2, start with a equilateral triangle with a side of 1. can you draw that for me?
In general, you need to do a complicated process to find the sine of an angle See http://www.homeschoolmath.net/teaching/sine_calculator.php In the old days, they hired people to work out the answers for each angle and put them in a book of tables. example http://www.grc.nasa.gov/WWW/k-12/airplane/tablsin.html However, there are a few angles where the sin of the angle is "easy" Here are the nice angles, and their sines angle (in degrees) Sin(angle) 0 0 30 1/2 45 sqrt(2)/2 60 sqrt(3)/2 90 1 People memorize these (and the cosine and tangent) if you know about 30-60-90 triangles, you can figure out the sin(30º) is 1/2
Join our real-time social learning platform and learn together with your friends!