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let f be a function with a second derivative by f"(x)=x^2(x-3)(x-6). what are the x-coordinates of the points of inflection of graph of f ?
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the answer is simple... put f"(x)= 0 you will get points of inflections answer is ...x=0, x=3,x=6
so I just plug in zero into the equation?
this answer shows the points of inflections of f(x) it can be solve by finding solution of f"(x)=0
have you got it...?
yes thanks
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wait i checked the answer and the point of inflection is only 3 and 6. why?
you have to make sure that f '' (x) changes in sign as you pass through each potential inflection point
this doesn't happen when you pass through x = 0, so that's why x = 0 is left out
thanks
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