Question

whats the integral for dx/x^2 + 16 ?

Answer 1

Trig sub perhaps?

Answer 2

i thinks its \[\frac{ \ln (x ^{2} +16)}{ 2 }+C\]

Answer 3

\[
x=4\tan\theta
\]

Answer 4

This is it right?\[
\int \frac{dx}{x^2+16}
\]

Answer 5

yep!

Answer 6

Wanna do a trig sub. You can't do the \(\ln(\;)\) thing unless the denominator is linear.

Answer 7

\[
x=4\tan\theta,\,dx=4\sec^2\theta \,d\theta
\]

Answer 8

Try this substitution and see what happens.

Answer 9

i'll doit, thanks!