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divide and simplify to lowest term. 2x^2-6x/3x-2 divided by x-3/3x-2 /= over
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Care to simplify the question?
or wait, I think I got it. another name for division is inverse multiplication.
So, \[\frac{ 2x^{2}-6x }{ 3x+2 } \div \frac{ x-3 }{ 3x+2 }\] is actually \[\frac{ 2x^{2}-6x }{ 3x+2 } \times \frac{ 3x+2 }{ x-3 }\]
Which ultimately gives you 2x.
|dw:1365353514295:dw| how does that turn into 2x?
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3x-2 in both places. :\
the +2 bit was a mistake (refer to the question asked)
oh ok. oops lol. thanks soo much :)
Glad to be of use. ;)
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