Question

(x+a)^2-(x+b)^2=a^2-b^2

Answer 1

what do you want?????

Answer 2

pls aswer equiation

Answer 3

use the identity for Difference of Squares i.e. m^2 - n^2 = (m+n)(m-n)

Answer 4

\[2ax+2bx=0 Use factor ??\]

Answer 5

(x+a)^2-(x+b)^2=a^2-b^2
[(x+a)+(x+b)]*[(x+a)-(x+b)]= (a+b)*(a-b)
[2x+a+b]*[a-b]=(a+b)*(a-b)
divide both sides by (a-b) and u get
2x+a+b=a+b
2x = a+b-a-b
2x =0
x=0/2
x=0

Answer 6

Thx so much

Answer 7

You can see that if we put x=0 in the original equation, we get

(0+a)^2-(0+b)^2=a^2-b^2
which gives
a^2-b^2=a^2-b^2

Answer 8

u r welcome ☺

Answer 9

yea can see thx