Question

Determine g-1(x) of the function g(x) = 12x + 6 where x≠ -3.
please help i have no idea how to do this

Answer 1

\[y=12x+6\]
solve for "x"
i.e.,
get \[x=\text{something in "y"}\]

Answer 2

i got 1/2-y=6x....
i dont think thats right

Answer 3

\[y=12x+6\\
y-6=12x\\
{y-6\over12}=x\]

Answer 4

get it now?

Answer 5

ohhhhhh got it!

Answer 6

but thats not an answer choice..

Answer 7

yep.
so,
\[g^{-1}(x)={x-6\over12}\]

Answer 8

can i show you my answer choices

Answer 9

a)g-1(x) = 2x - 6, x≠0
B)g-1(x) = 12x - 3, x≠0
C)g-1(x) = 12x - 6, x≠0
D)g-1(x) = 12x - 16, x≠0

Answer 10

ok..
seems to me like this is "RECIPROCAL" not INVERSE

Answer 11

wait one sec

Answer 12

it didnt show up right when i posted it

Answer 13

it should look like this