Question

solve system of equations:
y^2= x
x+2y+3= 0

Answer 1

substituting y^2 for x in the second equation;
y^2 +2y +3 = 0 solve for y using quadratic formula.
then solve for x substituting the values obtained for y, in one of the original equation.

Answer 2

yea I did that but I get imaginary numbers for y. so how do i get the x values ? i know i have to substitute them in the other equation but what should be the final answer ?

Answer 3

i get y= -1 + 1i sqrt 2 and y = -1- 1i sqrt 2 for x i get x= -1 plus or minus 2i sqrt 2