Question

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Answer 1

1.
c(2c+3+4d)+3d is the best this is getting.....
g(4g+12h+5)+15h is the best this is getting......
these can't be factored in this method because of the prime numbers involved.

Answer 2

Hope this helps!

Answer 3

Sure.

Answer 4

Srry was doing 5 question at once :D im so srry!

Answer 5

4g2 + 12gh + 5g + 15h
Group:
(4g2 + 12gh) + (5g + 15h)
Factor out the common factors:
4g (g + 3h) + 5 (g + 3h)
Use the distributive property:
(g + 3h) (4g + 5)

Answer 6

yes.

Answer 7

Sure.

Its Np i feel like im being a bother by doing so many question ;P

Answer 8

An easy to check to see if a quadratic is prime or not is to calculate the discriminant.

The discriminant of 2m^2 + 13m + 15 is:

b^2 - 4ac = 13^2 - 4(2)(15) = 169 - 120 = 49 = 7^2.

Since b^2 - 4ac is a perfect square, 2m^2 + 13m + 15 IS factorable and Tonya is correct.

On top of that, Diego is incorrect on how one needs to find factors of 15 that sum to 13. One needs to find factors of 2*15 = 30 that sum to 13 (which are easily seen to be 10 and 3).


Here is for the first one *remember dont copy and paste this is an example :P

Answer 9

2. to create a prime trinomial set a as 1 and then find a b and c that don't factor like b=5, c=2

Answer 10

@pinkmommy

so how did it go?

Answer 11

Np.

Answer 12

kinda stuck on that lol :d

Answer 13

http://openstudy.com/study#/updates/4fece276e4b0bbec5cfc6a58

try this

Answer 14

just look up Part 2: Create your own prime trinomial in the form ax2 + bx + c. Using complete sentences, explain how you know it is prime.
and you should get it.

Answer 15

K. looks right great job!

Answer 16

First this is a binomial (highest power is 2)

Any binomial is factorable using the quadratic formula, although there may be no real number solutions

So using quadratic formula with a=2; b=13; c= 15

m = (1/4)[-13 +/- sqrt[13^2 - 4(2)(15)]

m = (1/4)[-13 +/- sqrt(49)]

m = (1/4)(-20) = -5
and
m = (1/4)(-6) = -3/2

Solutions would be:
(x+5)(2x + 3)

Try this. http://answers.yahoo.com/question/index?qid=20100811133804AAydMB6

Answer 17

Yeah what school is this connections? K12?.

Answer 18

@pinkmommy Dont ever think that i am here to help.

Answer 19

forgive me laptop shut down

try this http://openstudy.com/study#/updates/500dd1b1e4b0ed432e104571

Answer 20

You there?

Answer 21

I would agree. somewhat.

*but i think that's the answer they are looking for.* also btw what grade lvl is this?

Answer 22

Ah. was thinking it would be higher but.

Answer 23

Fan me if you think you will have any other questions.

Answer 24

Looks like case closed after 2 hrs longest question ive ever had but it was a great learning experience for me to remember how to do this stuff.

Answer 25

Was so worth it though.

Answer 26

I will be doing more tomorrow soo i might be on.

Answer 27

lol i'm soo sorry.

Answer 28

Why are you srry.? It is my job to help around here .

that why i signed up for this gig :D*

Answer 29

So far ive been on for 11 days and ive got my smart score up to 58 which is pretty good.

Answer 30

lol well i appreciate it :) soo i gotta go lol i have school in the morning. thanks again :) byee

Answer 31

NP tc GL

Answer 32

I only answer 17 questions and i think ive had this account for a year lol pretty badd..

Answer 33

Questions Asked
6
Questions Answered
91
Medals Received
33

most of those question people took the answer and left :d

Answer 34

:D

Answer 35

yepp definitely beat me lol

Answer 36

Biology is a pain they never give medals

Answer 37

soo yeahh. lol i'll have more questions for you to answer and we'll talk soon :)

Answer 38

sorry i dont mean to be rude

Answer 39

Thats not rude thats a challenge :d

Answer 40

:)

Answer 41

Well tc GN hope all goes well

Answer 42

Cya!

Answer 43

Well you have way more fans i can tell you that :D