Mathematics
20 Online
OpenStudy (anonymous):
(x-4)(3x+1)-3(x-2)^2
HELP ME SOLVE!!!!
:(
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (mertsj):
It's not an equation...what is there to solve?
OpenStudy (anonymous):
Ooops!
(x-4)(3x+1) - 3(x-2)^2 > O
Solution set and graph.
OpenStudy (mertsj):
Better mulitply it out and collect like terms first then we'll go from there.
OpenStudy (anonymous):
I don"t know how to solve the 3(x-2)^2 :(
OpenStudy (mertsj):
Can you do (x-2)(x-2) ?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
I know the first part is 3x^2 -11x-4
OpenStudy (mertsj):
Then you can multiply (x-2)(x-2)
OpenStudy (anonymous):
x^2 - 4x + 4 ?
OpenStudy (mertsj):
And now that answer times -3
OpenStudy (anonymous):
-3x^2 +12x -12
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (mertsj):
So now we have:
\[3x^2-11x-4-3x^2+12x-12>0\]
OpenStudy (mertsj):
So collect the like terms
OpenStudy (anonymous):
x-16 ?
OpenStudy (mertsj):
yes x - 16 is greater than 0...don't forget that part.
Now add 16 to both sides and you're done.
OpenStudy (anonymous):
x > 16
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (mertsj):
Yeppers
OpenStudy (anonymous):
Would the Solution Set be (16, Infinity)
OpenStudy (anonymous):
Thank you @Mertsj !!!!!!
OpenStudy (mertsj):
yes. in interval notation that is the correct solution. You're welcome