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Mathematics 20 Online
OpenStudy (anonymous):

(x-4)(3x+1)-3(x-2)^2 HELP ME SOLVE!!!! :(

OpenStudy (mertsj):

It's not an equation...what is there to solve?

OpenStudy (anonymous):

Ooops! (x-4)(3x+1) - 3(x-2)^2 > O Solution set and graph.

OpenStudy (mertsj):

Better mulitply it out and collect like terms first then we'll go from there.

OpenStudy (anonymous):

I don"t know how to solve the 3(x-2)^2 :(

OpenStudy (mertsj):

Can you do (x-2)(x-2) ?

OpenStudy (anonymous):

I know the first part is 3x^2 -11x-4

OpenStudy (mertsj):

Then you can multiply (x-2)(x-2)

OpenStudy (anonymous):

x^2 - 4x + 4 ?

OpenStudy (mertsj):

And now that answer times -3

OpenStudy (anonymous):

-3x^2 +12x -12

OpenStudy (mertsj):

So now we have: \[3x^2-11x-4-3x^2+12x-12>0\]

OpenStudy (mertsj):

So collect the like terms

OpenStudy (anonymous):

x-16 ?

OpenStudy (mertsj):

yes x - 16 is greater than 0...don't forget that part. Now add 16 to both sides and you're done.

OpenStudy (anonymous):

x > 16

OpenStudy (mertsj):

Yeppers

OpenStudy (anonymous):

Would the Solution Set be (16, Infinity)

OpenStudy (anonymous):

Thank you @Mertsj !!!!!!

OpenStudy (mertsj):

yes. in interval notation that is the correct solution. You're welcome

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