Mathematics
8 Online
OpenStudy (anonymous):
Help
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jimthompson5910 (jim_thompson5910):
What is the perimeter of the first triangle
jimthompson5910 (jim_thompson5910):
any ideas?
OpenStudy (anonymous):
yea a+b+c =P
jimthompson5910 (jim_thompson5910):
ok so the first triangle has a perimeter of ____
OpenStudy (anonymous):
so 17 ror tri 1
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OpenStudy (anonymous):
for tri two 22
OpenStudy (anonymous):
for tri three 27
jimthompson5910 (jim_thompson5910):
all 3 are correct, nice work
OpenStudy (anonymous):
but we have to state some relation ship too
jimthompson5910 (jim_thompson5910):
ok let me think on that for a sec
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jimthompson5910 (jim_thompson5910):
the first term is 17
the second term is 22
the third term is 27
jimthompson5910 (jim_thompson5910):
to get the next term, you're adding 5
so this is an arithmetic sequence
jimthompson5910 (jim_thompson5910):
Hint:
|x-5| >= 3
turns into
x-5 >= 3 or x-5 <= 3
OpenStudy (anonymous):
x-5≥3 and x-5≤-3
x-5+3≥3+3 and x-5+3≤-3+3
x≥6 and x≤0
therefore,x≥6 and x≤0
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jimthompson5910 (jim_thompson5910):
oh you got it already lol
jimthompson5910 (jim_thompson5910):
sorta
OpenStudy (anonymous):
i gave her this answer she said my equation seup is not correct
jimthompson5910 (jim_thompson5910):
sry made a typo above, but fixed it
x-5 >= 3 or x-5 <= -3
x >= 3+5 or x <= -3+5
x >= 8 or x <= 2
OpenStudy (anonymous):
ok but do we have to write ≥ instead of >
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jimthompson5910 (jim_thompson5910):
turn every >= into ≥
turn every <= into ≤
OpenStudy (anonymous):
i got it
jimthompson5910 (jim_thompson5910):
ok great