Question

what is the range of f(x)=2x^2−20

Answer 1

y = 2x^2 - 20

is the same as

y = 2(x-0)^2 + (-20)

so it's in the form

y = a(x-h)^2 + k

Answer 2

the vertex is (h,k)

h = 0
k = -20

so the vertex is (0, -20)

which means that the lowest point on this graph is (0, -20)

Answer 3

any other point on y = 2x^2 - 20 will be above this lowest point and it stretches upwards forever to infinity

Answer 4

so it would be from (-20,0) then

Answer 5

[-20, infinity) actually

Answer 6

basically, the range is any y value from -20 onward to +infinity

Answer 7

than you

Answer 8

yw