EXPLANATION REQUIRED: If angles A,B and C of a triangle are in AP and if a,b, c denote the length of the sides opposite to A,B and C resp. Then the value of the expression (a/c)sin2C+(c/a)sin2A is?
well if they form an A..P with common difference d ,then they will have to satisfy the following when (x)+(x+d)+(x+2d)=180 where the terms in brackets are angles
i got x=60 but how to find 'd'?
how you got x=60 ?
3x+3d=180 then divide both the sides by 3
here's what i did THE ANGLES ARE: A B=A+d C=B+d whee A.B.C are in ap. now A+B+C=180 3A+3d=180 A+d=60 B=60
what is meant by AP?
arithmetic progression. where a series is given to you but the difference between any two consecutive numbers is the same.
thanks
does the poster of this question still need help?
yes..yes..
ok. are you familiar with side the ratios of the 30:60:90 triangle?
yup...
of so lets just take this bit by bit. so the fraction a/c can be re-written as what trigonometric identitiy?
remember SOH-CAH-TOA (if you've heard that before). you with me?
yh..yh.. so is it cot?
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no. sorry, it said it was written in AP so C should be the 90 degree angle
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ahhh, sorry about that, give me one sec
no problem. :)
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oki... you want me to tell you c/a with respect to which angle?
sorry a/c
well, you could write it a few ways but lets start evaluating the first part of the question (a/c)sin2C
if you are familiar with side ratio of 30:60:90 you will that the side ratio will be 1:root 3: 2
yup
so a/c is 1/root 3. now we can have a square root as the denominator so we multiple the top and bottom by root 3 and get (root 3)/ 3
now we multiply that my the next term which is sin(2C). C is 90 degrees so 2C is 180. what is the sin180?
0
yup, sorry for the delay, answering a physics question
0+root 3 sin60=2
c/a = 2
sin2A = Sin 60= 1/2
so (c/a)(sin60) = (1/2)(2)= 1
sin60=root3/2
you're right, i was looking at something else, i feel dumb.
thats okay..
so (1/2)(root3 / 2)
good?
but the answer is 2
are you telling me or asking me?
telling..
a/c=1/root 3 and c/a =root3 thats how you get two....
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