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Solve |x−3|<7. Write your answer in interval notation.
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if given |f(x)| < a (with a is a constant) then the solution is -a < f(x) < a
since absolute takes the positive and the negative number inside |number| @RadEn is right @spimentel
theforefore, if given |x−3|<7 then the solution can represented be -7 < x-3 < 7
simplify again add by 3 to all sides, giving us : -7+3 < x-3+3 < 7+3 -4 < x < 10
so how would i write that in interval notation?
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-4 < x < 10 that's already in interval notation
oh ok:) thank you soo much, i actually get it.:)
you're welcome :)
how would you write that with the infinity signs? because i think thats what its asking me
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