log(x+4) = log x + log 4
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log a+log b=log ab Use that on the right side.
log (x+4) = log (x times 4)
that is where I then go blank
x times x = 4x then cancel out the "log" from both sides
If the logs are equal and the bases are the same, then the arguments must be the same. x+4=4x
Okay. I wasn't sure that I could cancel the logs. So, x = 4/3
though one :P
yes
Thank you!
yw
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