What are the inflection points of the graph x^3 - 3x + 2?
A. The point of inflection are at (1, 0) and (-1, 4).
B. The point of inflection are at (0, 2) and (-1, 4).
C. The point of inflection is at (0, 2).
D. The point of inflection is at (0, -2).
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OpenStudy (mertsj):
Find the second derivative and find where it changes from positive to negative.
OpenStudy (anonymous):
the second derivative is 6x
OpenStudy (mertsj):
What do you think you should do with that second derivative?
OpenStudy (anonymous):
set equal to 0? and solve?
OpenStudy (mertsj):
Then do it.
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OpenStudy (anonymous):
ok i get x = 0
OpenStudy (mertsj):
That is the x coordinate of the inflection point. Plug that value back into the original function to find the y coordinate of the inflection point.
OpenStudy (anonymous):
plug it into x^3 - 3x + 2 ?
OpenStudy (mertsj):
Plug that value back into the original function
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
i get 2
OpenStudy (anonymous):
so its C
OpenStudy (anonymous):
@electrokid can u help?
OpenStudy (anonymous):
A plot is attached.
OpenStudy (anonymous):
okay so it is C
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OpenStudy (anonymous):
Yes. 6x is the second derivative. When set to zero, x = 0, y = 2