What are the inflection points of the graph x^3 - 3x + 2? A. The point of inflection are at (1, 0) and (-1, 4). B. The point of inflection are at (0, 2) and (-1, 4). C. The point of inflection is at (0, 2). D. The point of inflection is at (0, -2).
Find the second derivative and find where it changes from positive to negative.
the second derivative is 6x
What do you think you should do with that second derivative?
set equal to 0? and solve?
Then do it.
ok i get x = 0
That is the x coordinate of the inflection point. Plug that value back into the original function to find the y coordinate of the inflection point.
plug it into x^3 - 3x + 2 ?
Plug that value back into the original function
ok
i get 2
so its C
@electrokid can u help?
A plot is attached.
okay so it is C
Yes. 6x is the second derivative. When set to zero, x = 0, y = 2
okay
Thank you for the medal.
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