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Mathematics 18 Online
OpenStudy (anonymous):

What are the inflection points of the graph x^3 - 3x + 2? A. The point of inflection are at (1, 0) and (-1, 4). B. The point of inflection are at (0, 2) and (-1, 4). C. The point of inflection is at (0, 2). D. The point of inflection is at (0, -2).

OpenStudy (mertsj):

Find the second derivative and find where it changes from positive to negative.

OpenStudy (anonymous):

the second derivative is 6x

OpenStudy (mertsj):

What do you think you should do with that second derivative?

OpenStudy (anonymous):

set equal to 0? and solve?

OpenStudy (mertsj):

Then do it.

OpenStudy (anonymous):

ok i get x = 0

OpenStudy (mertsj):

That is the x coordinate of the inflection point. Plug that value back into the original function to find the y coordinate of the inflection point.

OpenStudy (anonymous):

plug it into x^3 - 3x + 2 ?

OpenStudy (mertsj):

Plug that value back into the original function

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

i get 2

OpenStudy (anonymous):

so its C

OpenStudy (anonymous):

@electrokid can u help?

OpenStudy (anonymous):

A plot is attached.

OpenStudy (anonymous):

okay so it is C

OpenStudy (anonymous):

Yes. 6x is the second derivative. When set to zero, x = 0, y = 2

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

Thank you for the medal.

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