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Identify the axis of symmetry for the quadratic function. y = x^2 + 2x – 3
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The x coordinate of the vertex is x = -b/2a. Since the axis of symmetry is a vertical line that passes through the vertex, that is also the equation of the axis of symmetry.
So it would be -2/2(1) , then -2/2 ?
So it would be x = -2/2 x=-1
some how i got (1,-2) let me redo mine..
but how did it become negative ?
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The graph would look like this?
b=2, therefore -b = -2
Oooooh okay I see now
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Thank You!(: I realize how to do it now!
yw
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