HELP! **PROOF** I GIVE MEDALS :) Finish the proof that BC≅DE Statement Reason 1) ? Given 2)∠BAC≅∠DAE ? 3)AC≅AE Given 4)? ? 5)BC≅DE
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@touseii45 think u could hel??
im not really good at proofs, never was lol but uhm maybe @jim_thompson5910 or @Mertsj can help
oh didn't kno though Id ask
which statement is given?
if possible, post a screenshot
something seems missing here
oops forgot sumthing in the proof AC≅AE is one given
ok that goes in statement 1
the first statement or statements are just repeating what's given
something else seems off it says ∠BAC≅∠DAC but angle DAC is a straight angle while BAC is not
oh it should be DAE sorry
ok so ∠BAC≅∠DAE right?
yes
ok so that's true because that's a common angle (it's really the same angle, just relabeled)
there are a few more ways to label that angle
ok
oh not sure why I didn't see AC≅AE in statement 3
how many statements are given?
3 statements #'s 2,3, and 5
I only see 4 statements total
sorry I put it in Statement Reason 1) ? Given 2)∠BAC≅∠DAE ? 3)AC≅AE Given 4)? ? 5)BC≅DE ?
ok ignore the table, what is given?
oh AC≅AE
ok what else
AB≅AD and BC≅DC
sure it's not BC and DE?
I ment BE and DC
Here's how I would fill out the proof table Statement Reason 1) ? Given 2) ∠BAC≅∠DAE ? 3) AC≅AE Given 4) ? ? 5) BC≅DE Statement Reason 1) AB ≅ AD Given 2) ∠BAC≅∠DAE ? 3) AC≅AE Given 4) ? ? 5) BC≅DE Statement Reason 1) AB ≅ AD Given 2) ∠BAC≅∠DAE Given 3) AC≅AE Given 4) ? ? 5) BC≅DE Statement Reason 1) AB ≅ AD Given 2) ∠BAC≅∠DAE Given 3) AC≅AE Given 4) △ABC = △ADE SAS Property 5) BC≅DE Statement Reason 1) AB ≅ AD Given 2) ∠BAC≅∠DAE Given 3) AC≅AE Given 4) △ABC = △ADE SAS Property 5) BC≅DE CPCTC
the idea is that you take the 3 given statements, then use the SAS property (with those 3 statements) then you use CPCTC to conclude that BC = DE
Ok thanks for your hel-:)
np
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