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Geometry 21 Online
OpenStudy (anonymous):

HELP! **PROOF** I GIVE MEDALS :) Finish the proof that BC≅DE Statement Reason 1) ? Given 2)∠BAC≅∠DAE ? 3)AC≅AE Given 4)? ? 5)BC≅DE

OpenStudy (anonymous):

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OpenStudy (anonymous):

@touseii45 think u could hel??

OpenStudy (anonymous):

im not really good at proofs, never was lol but uhm maybe @jim_thompson5910 or @Mertsj can help

OpenStudy (anonymous):

oh didn't kno though Id ask

jimthompson5910 (jim_thompson5910):

which statement is given?

jimthompson5910 (jim_thompson5910):

if possible, post a screenshot

jimthompson5910 (jim_thompson5910):

something seems missing here

OpenStudy (anonymous):

oops forgot sumthing in the proof AC≅AE is one given

jimthompson5910 (jim_thompson5910):

ok that goes in statement 1

jimthompson5910 (jim_thompson5910):

the first statement or statements are just repeating what's given

jimthompson5910 (jim_thompson5910):

something else seems off it says ∠BAC≅∠DAC but angle DAC is a straight angle while BAC is not

OpenStudy (anonymous):

oh it should be DAE sorry

jimthompson5910 (jim_thompson5910):

ok so ∠BAC≅∠DAE right?

OpenStudy (anonymous):

yes

jimthompson5910 (jim_thompson5910):

ok so that's true because that's a common angle (it's really the same angle, just relabeled)

jimthompson5910 (jim_thompson5910):

there are a few more ways to label that angle

OpenStudy (anonymous):

ok

jimthompson5910 (jim_thompson5910):

oh not sure why I didn't see AC≅AE in statement 3

jimthompson5910 (jim_thompson5910):

how many statements are given?

OpenStudy (anonymous):

3 statements #'s 2,3, and 5

jimthompson5910 (jim_thompson5910):

I only see 4 statements total

OpenStudy (anonymous):

sorry I put it in Statement Reason 1) ? Given 2)∠BAC≅∠DAE ? 3)AC≅AE Given 4)? ? 5)BC≅DE ?

jimthompson5910 (jim_thompson5910):

ok ignore the table, what is given?

OpenStudy (anonymous):

oh AC≅AE

jimthompson5910 (jim_thompson5910):

ok what else

OpenStudy (anonymous):

AB≅AD and BC≅DC

jimthompson5910 (jim_thompson5910):

sure it's not BC and DE?

OpenStudy (anonymous):

I ment BE and DC

jimthompson5910 (jim_thompson5910):

Here's how I would fill out the proof table Statement Reason 1) ? Given 2) ∠BAC≅∠DAE ? 3) AC≅AE Given 4) ? ? 5) BC≅DE Statement Reason 1) AB ≅ AD Given 2) ∠BAC≅∠DAE ? 3) AC≅AE Given 4) ? ? 5) BC≅DE Statement Reason 1) AB ≅ AD Given 2) ∠BAC≅∠DAE Given 3) AC≅AE Given 4) ? ? 5) BC≅DE Statement Reason 1) AB ≅ AD Given 2) ∠BAC≅∠DAE Given 3) AC≅AE Given 4) △ABC = △ADE SAS Property 5) BC≅DE Statement Reason 1) AB ≅ AD Given 2) ∠BAC≅∠DAE Given 3) AC≅AE Given 4) △ABC = △ADE SAS Property 5) BC≅DE CPCTC

jimthompson5910 (jim_thompson5910):

the idea is that you take the 3 given statements, then use the SAS property (with those 3 statements) then you use CPCTC to conclude that BC = DE

OpenStudy (anonymous):

Ok thanks for your hel-:)

jimthompson5910 (jim_thompson5910):

np

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