Question

Find the equation of the tangent line to the curve y=xsqrtx at the point (4,8).

Answer 1

well

\[x \sqrt{x} = \sqrt{x^3}\]

so write it in index form

\[y = x^{\frac{3}{2}}\]

makes it easy to differentiate

Answer 2

so the derivative was 3/2 x^1/2

Answer 3

yep... thats it... now substitute x = 4 to find the slope at (4, 8)

Answer 4

so i got for my equation y=3x-4 is that right

Answer 5

yep... make sense to me... well done

Answer 6

thanks