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I have the answer can somone please check me. What is the derivative of m(x)=ktan(kx) where k is the constant
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answer will be\[k^2(1+\tan^2 kx)\]is that what u got?
I got k^2cos^2(kx) is thatthe same thing
emm we have a formula as\[1+\tan^2 x=\frac{1}{\cos^2 x}\]so u will come up with\[\frac{k^2}{\cos^2 kx}\]
are u familiar with that formula? :)
yes ok I gotcha no thanks
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ok :)
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