Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

I have the answer can somone please check me. What is the derivative of m(x)=ktan(kx) where k is the constant

OpenStudy (anonymous):

answer will be\[k^2(1+\tan^2 kx)\]is that what u got?

OpenStudy (anonymous):

I got k^2cos^2(kx) is thatthe same thing

OpenStudy (anonymous):

emm we have a formula as\[1+\tan^2 x=\frac{1}{\cos^2 x}\]so u will come up with\[\frac{k^2}{\cos^2 kx}\]

OpenStudy (anonymous):

are u familiar with that formula? :)

OpenStudy (anonymous):

yes ok I gotcha no thanks

OpenStudy (anonymous):

ok :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
1 day ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
1 day ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!