Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

WXYZ is a quadrilateral in which w is 108 degrees x is 88 degrees y is 57 degrees and wxz us 31 degrees calculate wzx and xzy

OpenStudy (anonymous):

I know that z is 360 -108 -57-88 but what I don't understand is why wxz is 31 degrees

OpenStudy (anonymous):

|dw:1365670680470:dw|Does that diagram help a bit?

OpenStudy (anonymous):

This is a very interesting puzzle. Thanks for posting it! - "I don't understand is why wxz is 31 degrees" Quite simply, it's 31 degrees because they SAID it was 31 degrees. When I first reconstructed the quad from your description, I drew a zx line and wxz was far less than 31 degrees. Like you, this left me scratching my head. So then I drew a 31 degree angle and overlaid it on the wx line. That's when I saw the forehead slapper. It turns out that by defining wxz as 31 degrees, you're implicitly defining the length of wz! All I had to do was extend the wz line until z intersected the 31 degree line, and voila!! The quad came together! Of course, now knowing that wxz is 31 degrees, and w is 108, then wzx is obvious. Likewise, knowing that wxz is 31 degrees, then zxy must be 88-31. And since y is 57, then xzy is also now obvious.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!