Question

Solve and check

29x^2-20x=0

Answer 1

pull an x out

Answer 2

would you set them both to zero, such as 29x^2=0 and 20x=0?

Answer 3

absolutely not

Answer 4

okay then how would you pull an x out?

Answer 5

x(29x-20)=0

Answer 6

x=0
x=20/29

Answer 7

can you show me how your worked it out, I understand how you got the answer but the work behind it?

Answer 8

like a proof?

Answer 9

yeah

Answer 10

or the step you took to get the solution

Answer 11

Simplifying
29x2 + -20x = 0

Reorder the terms:
-20x + 29x2 = 0

Solving
-20x + 29x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), 'x'.
x(-20 + 29x) = 0

Subproblem 1
Set the factor 'x' equal to zero and attempt to solve:

Simplifying
x = 0

Solving
x = 0

Move all terms containing x to the left, all other terms to the right.

Simplifying
x = 0
Subproblem 2
Set the factor '(-20 + 29x)' equal to zero and attempt to solve:

Simplifying
-20 + 29x = 0

Solving
-20 + 29x = 0

Move all terms containing x to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 20 + 29x = 0 + 20

Combine like terms: -20 + 20 = 0
0 + 29x = 0 + 20
29x = 0 + 20

Combine like terms: 0 + 20 = 20
29x = 20

Divide each side by '29'.
x = 0.6896551724

Simplifying
x = 0.6896551724
Solution
x = {0, 0.6896551724}

Answer 12

x(29x-20)=0

x=0

>29x-20=0
>29x=20
>x=20/29

plug those back into the original equation and if it equals zero then it worked

Answer 13

thank you guys, Now I have to post a few more questions. you wanna take a stab at them?

Answer 14

@nathan917

Answer 15

sure.