Question

what is the definite integral of (1+x)^n when n is not equal to -1

Answer 1

u need integrate by u-sub, first

Answer 2

let u = 1+x
du = dx

Answer 3

now, that integral can be
int u^n du
= 1/(n+1) u^(n+1) + c

Answer 4

subtitute back that u = 1+x

Answer 5

so, it can be