Question

How do I set this up so that I get: 7/2 and -6/5?
10x^2-23x-42=0

Answer 1

i can try to solve it

Answer 2

\[10x ^{2}-23x-42=0\]

Answer 3

or,\[10x ^{2}-35x+12x-42=0\]

Answer 4

or,\[5x(2x-7)+6(2x-7)=0\]

Answer 5

or,\[(2x-7)(5x+6)=0\]

Answer 6

anyway r u following me

Answer 7

Does it always have to be broken down?

Answer 8

ya almost always

Answer 9

i think u r enough to do the rest of the math

Answer 10

How do you know which numbers to use when breaking it down, or does it not matter?

Answer 11

ya its matter

Answer 12

u need to factorise 10 and 42 first

Answer 13

wt u will get after factorise

Answer 14

u will get 5,2,2,3,7

Answer 15

i got 35 frm the multiplication of 5 and 7

Answer 16

and i got 12 frm the multiplication of 2,2,3

Answer 17

then i hv to subtract 12 frm 35 for getting -23

Answer 18

-35x+12x=-23x

Answer 19

and -35x*12x=(10x^2)(-42)

Answer 20

I get it now. I just have to practice more.