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Mathematics 13 Online
OpenStudy (anonymous):

What would the inequality be that represents this graph? And could someone explain it to me a bit, also? :/ http://imgur.com/0xVJtJN

OpenStudy (anonymous):

\[y \ge mx + c\] u guys agree with this? all there is left to do i find m and c

OpenStudy (anonymous):

@Zendemi15 u know how to find c and m?

OpenStudy (anonymous):

No :/

OpenStudy (anonymous):

sry for the late reply

OpenStudy (anonymous):

m is the gradient, and c is the y intercept, right?

OpenStudy (anonymous):

its okay

OpenStudy (anonymous):

yes :)

OpenStudy (anonymous):

Ok the gradient would be 0.5 then, right?

OpenStudy (anonymous):

so lets find c first, at wat pt does the graph touch the y-axis?

OpenStudy (anonymous):

0,-1 i think?

OpenStudy (anonymous):

wat were the two pts u chose to get that gradient?

OpenStudy (anonymous):

correct :) so c = -1 :)

OpenStudy (anonymous):

so y = mx - 1 is wat we found so far

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

how did u get that gradient?

OpenStudy (anonymous):

a chart thing my teacher showed me, about how the gradient is pretty much the steepness of the line and all that

OpenStudy (anonymous):

well ur teacher told u crap xD

OpenStudy (anonymous):

ill show i how to find the gradient of the line ;)

OpenStudy (anonymous):

Lol okay

OpenStudy (anonymous):

\[m=\frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }\]

OpenStudy (anonymous):

u r familiar with this formula?

OpenStudy (anonymous):

kinda

OpenStudy (anonymous):

that means no in my book so ill show u how to use it

OpenStudy (anonymous):

Lol okay xD

OpenStudy (anonymous):

ok so how this formula works is that u choose any two points on the line and plug in it's y and x value

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so u choose two pts now :P

OpenStudy (anonymous):

-2,-2 and 2, 2

OpenStudy (anonymous):

those rnt points on the line

OpenStudy (anonymous):

u have to choose two pts on the line (the line connecting the two arrow heads) not the pink region

OpenStudy (anonymous):

understand?

OpenStudy (anonymous):

Yeah.. I'm just tired and it's taking me a while to think lol 2,1 and 1,1

OpenStudy (anonymous):

i can understand that, would u rather i ust did it for u and explain wat i did?

OpenStudy (anonymous):

Yeah and then ill look over it again tomorrow so I'll understand it better

OpenStudy (anonymous):

and those rnt pts on the line either

OpenStudy (anonymous):

u want to go through it with me tomorrow as well?

OpenStudy (anonymous):

Yeah that would be great

OpenStudy (anonymous):

fine by me :) wat time will u be on?

OpenStudy (anonymous):

eh after i explain it ill organise that lol

OpenStudy (anonymous):

ok back to the question :)

OpenStudy (anonymous):

now ignore th pink region and just focus on the red arrow, cool?

OpenStudy (anonymous):

Alright

OpenStudy (anonymous):

0,-1 and 1,-1? o.O

OpenStudy (anonymous):

1, -1 isn't on the line

OpenStudy (anonymous):

look for places where the line crosses over an intersection of lines on the grid exactly.

OpenStudy (anonymous):

Just so the graph is a bit clearer.

OpenStudy (anonymous):

This is probably wrong, but 2,-2 and -3,3?

OpenStudy (anonymous):

do you know how to find the equation of a line?

OpenStudy (anonymous):

http://www.mathsisfun.com/equation_of_line.html

OpenStudy (anonymous):

oh, I see. you need to know how to find the slope. Start at the point you already found, (0, -1) Move along the line until you find another point with integers as y and x values m= the horizontal distance you went / the vertical distance you went

Directrix (directrix):

The dashed line intersects the point (0,-1) which means that the y-intercept is -1. To get the slope from the graph, I looked for two points both with integer coordinates that appear to be points on the dashed line. I chose (-3,-3) and (0,-1). From (-3,-3) I counted 3 units to the right to get underneath the point (0,-1). That took me to the point (0,-3) from which I counted 2 units up to reach the point (0,-1). For slope, the change in x is 3, and the change in y is 2. The slope of the dashed line is 2/3. Using the slope-intercept form of a line: y = mx + b, then the equation of the dashed line is y = (2/3) x - 1. The shaded section is above the dashed line. Its equation is y > (2/3)x - 1. --> Please check my work. @Zendemi15

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