Question

(2/(x-2))-(8/(x^2-4))

Answer 1

expand x2 -4 as (x+2)(x-2)

Answer 2

if someone could show me the steps on how to cross multiply and simplify this i would appreciate it

Answer 3

So, \[\frac{2}{x-2}-\frac{8}{x^2-4}\] Yah, start lik what Koel said. Then get a common denominator, do the subtraction, and finish. Because it is a negative, not an equals, it is not really a cross multiply.

Answer 4

2/x-2 - 8/x2 -4

=2/x-2 -8/(x+2)(x-2)

multiply the numerator and denominator of the first term with x+2(because that's what is missing)

=[2(x+2) -8 ]/(x+2)(x-2)

=(2x+4-8)/(x+2)(x-2)

=2x-4/(x+2)(x-2)

=2(x-2)/(x+2)(x-2)

=2/x+2

Answer 5

thank you so much! took me a while to see it but i finally understand it now. thank you