Find the roots of :
x^2+11x=-30
3x^2+2x-4=0
5 sqrt x -x=6
x^2-8=17
CAN ANYBODY HELP ME PLEASE WORK THESE OUT !?!

Question

anonymous · Answer

This site explains how to find roots and gives some good examples: http://www.freemathhelp.com/finding-roots.html

madhatter · Answer

1st one is x=60

anonymous · Answer

Hmm, I am not getting 60, perhaps if you show your work how you came about that @madhatter ?

When I do it I get a simplified equation of:
x^2+11x=-30 --> (x+5)(x+6) 
meaning its roots are at x=-5 and x=-6

madhatter · Answer

2nd one is x=24

madhatter · Answer

just do it like a norm equation its easy

anonymous · Answer

@madhatter If you plug 24 into the second equation...

3x^2+2x-4=0
3(24)^2+2(24)-4=0
1728+48-4=0

This is not right :/ as it does not equal 0, might be useful if you show your work for how you are getting those answers for @Rea731

anonymous · Answer

@edlevin the first problem you did is correct

anonymous · Answer

Yup, if you follow the same procedure for the others you should find those values also, if you would like to post what you did I can check them for you :)

anonymous · Answer

I am having a problem solving the second one|dw:1365717729797:dw|