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Mathematics 18 Online
OpenStudy (anonymous):

Can someone help me out? Explain step by step. I know how to graph but how do you go opposite like it says? http://imageshack.us/f/339/screenshot20130411at900.png/

OpenStudy (mertsj):

So...as I asked before...have you been studying absolute value functions?

OpenStudy (anonymous):

Well you see i'm practically done with Algebra 2.. I'm retaking the course online and this is a review of Algebra 1 supposedly... I forgot everything..

OpenStudy (anonymous):

So I guess no.. I havnt..

OpenStudy (mertsj):

When you have a graph that is a V such as your graph it is the graph of something related to this: y=|x|.

OpenStudy (mertsj):

Think of some ordered pairs that would be on that graph: (0,0) (1,1), ) (-1,1) (2,2) (-2,2) (3,3) (-3,3) and so on.

OpenStudy (mertsj):

Can you graph those ordered pairs?

OpenStudy (anonymous):

yes

OpenStudy (mertsj):

Do you agree that that graph would look like this:

OpenStudy (mertsj):

|dw:1365729349649:dw|

OpenStudy (anonymous):

yes

OpenStudy (mertsj):

And if it were and inequality such as y>=|x| it would look like this:

OpenStudy (mertsj):

|dw:1365729434275:dw|

OpenStudy (mertsj):

And if it were an inequality such as this: y<=|x| it would look like this:

OpenStudy (mertsj):

|dw:1365729495427:dw|

OpenStudy (anonymous):

oh yeah I remember this

OpenStudy (mertsj):

And if the line were a dotted line like in your graph, it would be the same except it would be y<|x| or y>|x| without the equal to part.

OpenStudy (mertsj):

Are you with me so far?

OpenStudy (anonymous):

yeah

OpenStudy (mertsj):

And so your graph is like this except it has been moved 2 spaces to the left and 3 spaces down. Do you see that?

OpenStudy (anonymous):

yeah

OpenStudy (mertsj):

So that affects the equation like this: y=|x-h|+k is the equation of one of these V's that has been moved h units right or left and k units up or down.

OpenStudy (mertsj):

So in your case, since it has been moved 2 units to the left we have y=|x--2|

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