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Mathematics 18 Online
OpenStudy (anonymous):

I need help finding the solutions of the system. i fan and Medal 1. y=x²+3x-4 y=2x+2 2. y+x²-2x-2 y=4x+5

OpenStudy (anonymous):

some typos here?

OpenStudy (anonymous):

\[y=x^2+3x-4\] \[y=2x+2\] set \[2x+2=x^2+3x-4\] and solve for\(x\)

OpenStudy (anonymous):

start by setting equal to zero, then solve the quadratic equation \[2x+2=x^2+3x-4\] \[x^2+x-6=0\] factor \[(x-2)(x+3)=0\] set each factor equal to zero and solve

OpenStudy (anonymous):

second one is similar, set \[x^2-2x-2=4x+5\]

OpenStudy (anonymous):

ok x-2=0 +2 +2 x=2 x+3=0 -3 -3 x=3 So no slutions?

OpenStudy (anonymous):

@amistre64 ^ is this what he was talking about?

OpenStudy (anonymous):

(or she)

OpenStudy (amistre64):

that is what he is talking about yes, but why would you conclude NO solutions?

OpenStudy (anonymous):

because they aren't the same number?

OpenStudy (amistre64):

the solution to a curve and a line will have either 2 solutions|dw:1365970152736:dw| 1 solution |dw:1365970174462:dw| or no real solutions |dw:1365970197889:dw|

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