Question

(x+1/x)3 solve by indefinite integration

Answer 1

expand it out and work the pieces

Answer 2

by using (a+b)3
formula

Answer 3

yes

Answer 4

\[\int\limits(x+\frac{ 1 }{ x })]dx
=\[intxdx+\int1/x)dx
=\[x^{2}/2+logx+c\]

Answer 5

the posted problem has a ^3 attached to it. so you can just plow the integral thru like that.

Answer 6

but once it is expanded out, that would be the process yes

Answer 7

(x+1/x)^3=x^3+1/x^3+3(x+1/x)
.X3+1/x^(3 ) +3*x*1/x(x+1/x)=x3+1/x^3 +3x+3/x=x3+x-3+3x+3*1/x
∫▒〖(x+1/x〗) 3dx=∫▒x^3 dx+∫▒x^(-3) dx+3∫▒x dx+3∫▒1/x dx
= x^4/4+x^(-2)/(-2)+〖3x〗^2/2+3logx+c