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please help me with this trig.. sinu=3/5 and sinv=4/5, evaluate sin(u-v) and tan(u+v)
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Firstly you should calculate cos(u) and cos(v). Do you know how you will calculate these?
no i do not
See, we have an identity which says: \[\sin^2(x) + \cos^2(x) = 1\] Here let us find out the value of cos(x). \[\cos^2(x) = 1- \sin^2(x)\] \[\implies \cos(x) = \sqrt{1 - \sin^2(x)}\] Getting this much?
oh ok i can do that, then do i use sin(u-v)=sinucosv-cosusinv?
Yep...
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Firstly find cos(u) and cos(v) by using the formula I wrote above.. Then use that formula you wrote..
thank you very much friend, you're the best
You are welcome dear.. And I can be better but I am not the best..
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