Question

what are the solutions to... (equation drawn)

Answer 1

\[x-2=\sqrt{2x-1}\]

Answer 2

1st step: square both sides of the equation and what do you get???

Answer 3

x^2-4x+4=2x-1

Answer 4

yes....you got that right!

Answer 5

2nd step: send all the terms to one side of the equation and what do you get??

Answer 6

x^2-6x+5

Answer 7

you meant if you send all the terms to the other side, the equal sign cannot disappear like that rather you would be left with nothing (which is zero) on the other side of the equation...

Answer 8

so what do you get??

Answer 9

x^2-6x+5=0

Answer 10

yes...that is right!
Do you know the quadratic formula???

Answer 11

yes but i factored the equation out and got (x-5) and (x-1) and set them equal to 0 and got that x= 1 and 5

Answer 12

okay.....you used the factorisation method!!
so that is it! you get the answers right!

Answer 13

**got

Answer 14

sorry about that lol

Answer 15

but thanks so much!!

Answer 16

you are welcome!....:)