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\[e ^{x}e ^{x+1} = 1\]
e^(2x+1)=1 right?
take ln of both sides
ok
you add the exponents since they have same base to get e^(2x+1)=1 now just take ln of both sides
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10.01000077 = 0 ????
\[\large \ln 1=2x+1\] \[\large 0=2x+1\]
oh ok
2*x+1=ln(1) took ln of both sides ln(1)=0 use this fact so 2x+1=0 canyou solve that
sorry! lol its late! and yes i can thanks!!!
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thanks for medal
yw
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