Question

solve the system by elimination

Answer 1

please show all work

Answer 2

@waterineyes help!?

Answer 3

Can you add 1 and 3 equations??

Answer 4

what do i do?

Answer 5

-2x + 2y + 3z = 0
2x + 3y + 3z = 5

Just add them..

Answer 6

so it would be 5y+6z=5?

Answer 7

Yep good..

Answer 8

so now what?

Answer 9

Now add second and third equation..

Answer 10

sooo 2y+4z=2?

Answer 11

Yep,
Now you have two equations:
5y + 6z = 5
2y + 4z = 2

Can you solve them to find y and z or not??

Answer 12

nootttttt

Answer 13

Multiply first equation by 2 and second by 5.

Answer 14

ok hold on

Answer 15

Take your time..

Answer 16

so 10y+12z=10
10y+20z=10?

Answer 17

Going very nice..
Good.

Now subtract both the equations...

Answer 18

8z=0

Answer 19

Okay, or -8z = 0 (if you have done like this 12z - 20z = 0_

Nevermind.

So what is z now??

Answer 20

8z = 0, so z is??

Answer 21

so z=0?

Answer 22

Yep, now put z = 0 in any one of the two equations and find y there..

Answer 23

oka hold on

Answer 24

Take your time..

Answer 25

y=1?

Answer 26

Yep,
So z = 0 and y = 1 now find x by putting y and z in any one of three equations you earlier have at the starting..

Answer 27

x=-1?

Answer 28

Let me check, I have not checked yet for x..

Answer 29

take your time ;)

Answer 30

x = -1 ??

Check it again, which equation you are putting y and z??

Answer 31

-2x+2y+3z=0

Answer 32

So plug in the values carefully..

Answer 33

Check it once again and take your time :P

Answer 34

sooo not -1? just 1?

Answer 35

Yep..

Because by putting z = 0 you will get:
-2x + 2y = 0

Subtract 2y from both the sides:

-2x = -2y

Now multiply by -1 to cancel minus both the sides:

2x = 2y

Putting y = 1:

2x = 2

Divide by 2 both the sides

x = 1..

Answer 36

YAY!!!!! is that it??

Answer 37

So you got: x = 1, y = 1 and z = 0 and that's it..

Answer 38

thank you so much for your patience by the way

Answer 39

You are welcome dear..