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Find all rational, irrational, and complex zeros.
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x^4-81
Can you factor it? It is the difference of two squares.
the best i coulve did was x^4-3^4
Think of it like this: \[(x^2)^2-(9)^2\]
And use this: \[a^2-b^2=(a-b)(a+b)\]
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oh, so then it would be (x^2-9)(x^2-9)?
oh lemme do that really quick
Did you notice the + sign?
yes
And then x^2-9 will factor again.
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so the rational is +3, and -3.
\[x^4-81=(x^2-9)(x^2+9)=(x-3)(x+3)(x^2+9)\]
Yes. And the complex?
umm. is it +3i and -3i?
It is. Good job!!
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so are there any irrational ?
x^4 has 4 roots and we have found 4 roots. So what do you think?
oh. ic, thanks for your help.
yw
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