Question

Suppose that x=x(t) and y=y(t) are both functions of t. If
y^2+xy−3x=−3
and dy/dt=1 when x=2 and y=1, what is dx/dt?

Answer 1

implicit diff?

Answer 2

i get confuse on what notation to use would i put dy/dx or when do i put dx/dt

Answer 3

what have you done

Answer 4

well the way i have it so far is 2y dy/dt +x dy/dt + y dx/dt - 3 dx/dt=0

Answer 5

You got that right. Now just plug in all the given values, you will be able to solve for dx/dt