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rationalize the denominator of 5/2sqrt.of3
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\[\frac{5}{2\sqrt{3}}=\frac{5}{2\sqrt{3}}\times \frac{\sqrt{3}}{\sqrt{3}}\] \[\large =\frac{5\sqrt{3}}{2(3)}\] \[\large =\frac{5\sqrt{3}}{6}\]
You have to just get rid of the square root int he denominator when rationalising. And you know when you don't want a square root sign, you multiply the square root of the number with a square root of the same number. That's all to it.
in the*
Thanks so much. :)
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