I really need help with this problem. If anyone could at least guide me in the right direction I'll be grateful! Show that among all isosceles triangles whose equal sides have equal length L, the triangle of largest area is a right triangle
try it... get the area of an isosceles triangle with two sides of length L and θ the angle between them
L being a constant, of course.
How would I get the area and angle without any numerical values? I thing not having any numbers to work with is my biggest problem right now...
Algebra :) Let's draw an isosceles triangle, only, let's draw it like this, it's easier to see things this way... L is what's called a parameter... not quite a variable, for all intents and purposes, it's a constant. |dw:1366032574568:dw|
now the angle|dw:1366032623037:dw|
|dw:1366032755786:dw|
Ok I somewhat see where you are going... Is there some kind of equation that goes with this?
Of course :) What's the formula for the area of a triangle?
1/2bh
Yeah... so in this case, our base is L, right?
Yep
What's our height (h) ?|dw:1366032936354:dw|
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