If the radius of the base of a cone is doubled and the height remains the same (below), what is the change in the volume from Fig. I to Fig. II?

Question

anonymous · Answer

attachment

anonymous · Answer

a. It is two times larger
b. It is three times larger.
c. It is four times larger
d. It remains the same.

anonymous · Answer

@ryan123345

ryan123345 · Answer

Lets say the radius is 2. Lets try it. The formula is$$\frac{ 1 }{ 3 }Bh$$

anonymous · Answer

1/3*2*h ?

ryan123345 · Answer

no B stands for area of base

ryan123345 · Answer

so it would be 1/3*12.57*4       (lets say the height is 4)

ryan123345 · Answer

Thats for the first one ^ what do you think you'll get?

ryan123345 · Answer

1/3*50.27*4                   (for the second one)

ryan123345 · Answer

16.76   and     67.04.       What can you multiply 16.76 by to get 67.04?

ryan123345 · Answer

@lana.831

anonymous · Answer

4

ryan123345 · Answer

Great Job! Then its four times larger :)

anonymous · Answer

oh okay, thanks!