Determine the coordinates of the x-intercepts for the quadratic equation 5x^2 – 21x + 4 = 0.
Just make the factors of it and then find x..
i dont know how to factor
first you multiply the 5 with 4, so you get 20 and then you have to find two numbers that give you 20 when you multiply them and give you a sum of -21 when you add them
I'll show you an easy example so that you learn how to factorize. \[2x ^{2}+5x+3\]
2x3=6 and 2+3=5
so you basically split the middle term into 2x+3x
now you have a new equation that looks like this \[2x ^{2}+2x+3x+3\]
then you factorize like this: \[2(x+1)+3(x+1) so the (x+1) is common for both of them
i forgot the x after the 2
so it's (2x+3)(x+1)
Do you get it?
you can check if it's right by just expanding the brackets... do you know how to expand?
i still dont get it my teacher is kinda teaching me slowly
okay factorising is when you try to break down the equation to its components
you do that by finding common factors
yeah
you get this?
kinda
so you need to split the middle term(in my example it's the 5x) to split it means that you have to first multiply the number in front of the x^2 with the last number and then you find a number that will give you the 5 in the middle when you add them and the number you got when you multiplied
like my example it was 2 and 3... because 2+3=5
and 2*3=6
with me?
yea im with you
do you get how we split the middle term
yeah it mean you first muilitply the number in front of x^2
with the last number which is 3 here
so you get 6
you example or my example?
well my example is easier to understand if you haven't done this before
and it's much easier if your teacher explains it to you right in front of you so you can see it step by step
yeah i know, can we use my example?
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