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Mathematics 17 Online
OpenStudy (anonymous):

Need help with Finding the measurements for this figure.

OpenStudy (anonymous):

OpenStudy (anonymous):

i need to find the Slant height

OpenStudy (anonymous):

options are a. 15.6 units b.13 units c.2√(11) units

OpenStudy (anonymous):

This is just forming the right angled triangle.. |dw:1366057760579:dw|

OpenStudy (anonymous):

You need to find here x.. Use pythagorean theorem to find x: \[x^2 = 12^2 + 5^2 \]

OpenStudy (anonymous):

i dont know?

OpenStudy (anonymous):

Simply tell me \(12^2\) = ??

OpenStudy (anonymous):

Wait or may be I am wrong, wait a minute..

OpenStudy (anonymous):

Never mind, we are going in right direction..

OpenStudy (anonymous):

Can you tell me what is \(12^2\) ??

OpenStudy (anonymous):

\(12^2\) is same as \(12 \times 12\) now can you find it??

OpenStudy (anonymous):

What happened??

OpenStudy (anonymous):

oh that would be 144

OpenStudy (anonymous):

Yep, similarly, \(5^2\) would be??

OpenStudy (anonymous):

\(5^2\) is same as \(5 \times 5\) = ??

OpenStudy (anonymous):

25

OpenStudy (anonymous):

Yep S0: \[x^2 = 144 + 25\] 144 + 25 = ?

OpenStudy (anonymous):

169

OpenStudy (anonymous):

Yep and can you take square root of it??

OpenStudy (anonymous):

\[x^2 = 169 \implies x = \sqrt{169} = ??\]

OpenStudy (anonymous):

13?

OpenStudy (anonymous):

Yep, Good..

OpenStudy (anonymous):

Getting how we have done this??

OpenStudy (anonymous):

ya thanks alot

OpenStudy (anonymous):

You are welcome dear..

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