Find the equation of the line that goes through the points (-2, -1) and (2, -5).
to write the equation of a line you need a slope and a y intercept, Do you know how to find the slope?
y=mx+b
thats the slope intercept form of a line. Slope formula given two points is y2-y1/x2-x1 -5 --1/2 --1 tell me what you get
3/2
-5 - -1 -5 +1 = -4 minus a neg, is same as addition ________ 2 - - 2 2 + 2 = 4 slope is -4/4, = -1 do you see where I got that?
Yes, I didn't see the - in front of the 5
now that you have a slope, how do you find the equation? using point slope or y = mx + b? your choice
y=mx+b
pick one of the points doesnt matter which one....which ever..
x y say (-2, -1), subsitute this and slope into y = mx + b -1 = -1(-2) + b , b is the y intercept, solve for b
(-2,-1) y=mx+b -1=-1(-2)+b -1=2+b -2 -2 -3=b b=-3
great! now you have a slope and a y intercpet for your line. m = -1, b = -3, just substitute them into y = mx + b y = -1x - 3 or y = -x -3
ok. Thanks
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