. Which of the following is the equation of a circle with a radius of 2 and its center at (4, 3)? (Points : 5) (x 4)2 + (y + 3)2 = 2 (x + 4)2 + (y 3)2 = 2 (x 4)2 + (y + 3)2 = 4 (x + 4)2 + (y 3)2 = 4 I think it is b but i am unsure
is it (x - 3)^2 + (y - 2)^2 = 4
i mean -4
the center is (4, 3), so the left side should be (x - 4)^2 + (y - 3)^2
idk how you got (x - 3)^2 + (y - 2)^2
lol yeah I kinda have a messed up calculator :( lol
no need for a calculator since you're just plugging in (or replacing) variables with numbers
thats probaby how im confusing myself ugh lol
maybe, i guess that's a sign you're probably too dependent on your calculator, but idk
but all you're doing is going from (x-h)^2+(y-k)^2=r^2 to (x-4)^2+(y-3)^2=2^2 .. replace h with 4, k with 3, r with 2 (x-4)^2+(y-3)^2=4
yeah i kinda am lol ever since highschool all the teachers would say is use your calculator not ur head you could be wrong but the calculata is always right lol
well if you type it in wrong, then the calculator is wrong it does exactly what it's told to do
they also say if you dont know the answer then "guess" but i feel like thats kinda stupid lol
yeah so true
and calculators don't handle everything...otherwise, why not just hand the job over to the calculator
well they're teaching to the test because you can't guess if it isn't multiple choice
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