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Mathematics 19 Online
OpenStudy (anonymous):

Help with Algebra please! so appreciated

OpenStudy (anonymous):

OpenStudy (anonymous):

Can anyone help with that?

OpenStudy (anonymous):

I can but I need to know what the definition of a parabola is.

OpenStudy (anonymous):

B

OpenStudy (anonymous):

A plane curve formed by the intersection of a right circular cone and a plane parallel to an element of the cone or by the locus of points equidistant from a fixed line and a fixed point not on the line.

OpenStudy (anonymous):

Does that help Speedy?

OpenStudy (anonymous):

no need to use the definition of a parabola here, the sign of x^2 >0 means the parabola is upward. done

OpenStudy (anonymous):

Thank you so much. Could you help me with more? If not I understand. I am just really having trouble, and do not get it.

OpenStudy (anonymous):

ok, which one?

OpenStudy (anonymous):

OpenStudy (anonymous):

I do not know why it says im replying when im not

OpenStudy (anonymous):

min

OpenStudy (anonymous):

OpenStudy (anonymous):

because the form of it is a form of upward parabola, to that kind, parabola has minimum value only, it's its vertex.

OpenStudy (anonymous):

new question?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

y - axis

OpenStudy (anonymous):

How do I find the axis?

OpenStudy (anonymous):

your parabola is upward, since its form is y = x^2..... so the symmetric axis MUST BE y-axis

OpenStudy (anonymous):

@Brookebrookiee Do you having a graphing calculator?

OpenStudy (anonymous):

No I do not

OpenStudy (anonymous):

Okay, if someone tells you the answer you will never understand how to solve this on a test. Go to this link to use a website graphing calculator: http://my.hrw.com/math06_07/nsmedia/tools/Graph_Calculator/graphCalc.html Then next, you type the first function in, check to see if it opens upwards. Do this for all of the functions and you will figure out the right answer.

OpenStudy (anonymous):

Okay, thank you! I appreciate your help Leaper

OpenStudy (anonymous):

How would I put this in a calculator

OpenStudy (anonymous):

Brookebrookiee my response was to your first question at the beginning.

OpenStudy (anonymous):

How would I do number 3? I'm sorry I dont understand what to do

OpenStudy (anonymous):

@Brookebrookiee Go to the online graphing calculator, type in that function and then the axis of symmetry is the x value that is at the very bottom of the graph.

OpenStudy (anonymous):

Okay, so I would type in x^2+2x-3, on the part of the calculator that says y1?

OpenStudy (anonymous):

Yes, then tell me the answer you got and I will tell you if I got the same answer as you.

OpenStudy (anonymous):

Okay I got -4?

OpenStudy (anonymous):

The axis of symmetry is the x value not the y value.

OpenStudy (anonymous):

If it is the x value, what did you get?

OpenStudy (anonymous):

ok but on the graph the paraobla goes on two points?

OpenStudy (anonymous):

The axis of symmetry is the x value at the very bottom of the parabola

OpenStudy (anonymous):

You figured out the y value of the very bottom of the parabola which was -4.

OpenStudy (anonymous):

You understand how coordinates work right?

OpenStudy (anonymous):

this is what my screen looks like

OpenStudy (anonymous):

I know it's very hard to see but if you were to put a ruler to your monitor, the coordinates the bottom of the parabola is (-1, -4)

OpenStudy (anonymous):

Do you get it now? The axis of symmetry is the x value of the bottom of the parabola.

OpenStudy (anonymous):

Okay, i think so

OpenStudy (anonymous):

x = -1 is the answer.

OpenStudy (anonymous):

how do I find the vertex?

OpenStudy (anonymous):

Vertex is the very bottom of a parabola. Do you have a picture of a parabola?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

@Brookebrookiee Watch this video it will help a lot! https://www.khanacademy.org/math/trigonometry/polynomial_and_rational/solving_graphing_quadratics/v/quadratic-functions-2

OpenStudy (anonymous):

I have to find the vertex of that eqaution now

OpenStudy (anonymous):

That video will help you, please watch it. I have to go now.

OpenStudy (anonymous):

ok, thanks for the help Leaper

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