Factoring Question. [MEDAL FOR BEST ANSWER.♥ Thanks in Advance.]
\[4x ^{3}-12x ^{2}+8x=0\]
First, look at all terms and try to factor the largest factor possible.
x=0,1
What is the largest common factor in 4, 12, and 8?
4.
Good. What is the largest common factor in x^3, x^2 and x?
X. \[4x(x^{2}-3x+2)=0\]?
Great. Next step is to try to factor the trinomial in parentheses. It is of the form x^2 + bx + c You write two sets of parentheses with x on left side: (x )(x )
What goes in right side of parentheses is 2 numbers that multiply to b and add to c. In your case, you need two numbers which multiply to 2 and add to -3
What two numbers have a product of 2 and a sum of -3?
Okay... (x-2)(x-1)?
OHH. So then it would be, 0,1, and 2?
Correct, so the complete factorization is: 4x(x-2)(x-1)
0, 1, and 2 are what x is equal to if you set the original trinomial equal to zero and solve the equation for x.
Thank you! c'; *Tears Up* So helpful...
cx
you're very welcome
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