Question

Help me please !!!!

Answer 1

10th term:
\[6, 6\frac{ 2 }{ 3 }, 7 \frac{ 1 }{ 3 }, ...\]

Answer 2

http://www.mathwords.com/a/arithmetic_sequence.htm

Answer 3

if you're going to hack it.....then there is only one way the series is simple arithmetic progression you can observe this series as

( 18/3...20/3....22/3.....) commcon difference is 2/3

Answer 4

plug in numbers to get 12 i think

Answer 5

thanks(: